[nadavaha]

Hi,
so I just ran into the API change for bluetooth sockets between the older versions and the 1.9.1+ versions.

I want my application to run under older and newer versions, so I would like to check the pys60 version number.
I tried sys.version, but that's the python core version (2.5.1).

Does anyone know what's the right way to check versions and perhaps even the standard check whether the version is higher than a certain number or lower than it?

thanks!

[Rafael T.]

You can use e32 module:

import e32

print e32.pys60_version

Hope it helps,

Rafael.

[nadavaha]

Thanks, that did the trick!

In case it helps others, here's what I did:

from e32 import pys60_version
if ((pys60_version.split())[0] >= '1.9.1'):
    import btsocket as socket
else:
   import socket

I did it for the bluetooth sockets, but you can put any other compatibility issue there...

Nadav

[marcelobarrosalmeida]

My way:

import e32
if float(e32.pys60_version[:3]) >= 1.9:
    import btsocket as socket
else:
    import socket

I don´t know if it will be usable/portable for all future version of 1.4.x and 1.9.x but ... I *think* I am prepared !

[croozeus]

Originally Posted by marcelobarrosalmeida

My way:

import e32
if float(e32.pys60_version[:3]) >= 1.9:
    import btsocket as socket
else:
    import socket

I don´t know if it will be usable/portable for all future version of 1.4.x and 1.9.x but ... I *think* I am prepared !

Good One!

[JOM]

Originally Posted by marcelobarrosalmeida

import e32
if float(e32.pys60_version[:3]) >= 1.9:
    import btsocket as socket
else:
    import socket

I don´t know if it will be usable/portable for all future version of 1.4.x and 1.9.x but ... I *think* I am prepared !

Sorry, too little sleep:

1) Wouldn't simpler & faster text string comparison also work? For example "2.0" is bigger than "1.9" even as text strings?

2) Would your check fail, when major version gets over 9? "10." is not valid float, is it

Sleepy,

--jouni

[marcelobarrosalmeida]

Yes, JOM is right, again ...
Thanks to foreseen the mistake.

But I think both approach have problems, in different situations:

>>> "2.10">"2.4"
False

But, I know, if we want just to check 1.x against 2.y, a simple string comparison is enough, as indicated by JOM. This seemed a simple question ...

In my code (wordmobi), I defined versions like x.y.z, I mean, 3 numbers separated by ".". Each number with one or two digits. And I used this function:

def ver2num(ver):
    a,b,c = map(lambda x,y: x*y, [10000,100,1],[int(v) for v in ver.split(".")])
    return a+b+c

An integer is returned but it costs a lot to process ...

[Rafael T.]

Another simple way would be removing the dots, so 1.9.1 would be 191, for example.

ver = e32.pys60_version
d_ver = int(ver[:6].replace(".", ""))

if d_ver >= 191:
    import btsocket as socket

else:
    import socket

BR,

Rafael.

[mahesh.sayibabu]

Originally Posted by nadavaha

Hi,
so I just ran into the API change for bluetooth sockets between the older versions and the 1.9.1+ versions.

I want my application to run under older and newer versions, so I would like to check the pys60 version number.
I tried sys.version, but that's the python core version (2.5.1).

Does anyone know what's the right way to check versions and perhaps even the standard check whether the version is higher than a certain number or lower than it?

thanks!

This should work on both the PyS60 series

try:
    import btsocket as socket
except:
    import socket

====
Mahesh
PyS60 Team

[aaaaapo]

Originally Posted by JOM

1) Wouldn't simpler & faster text string comparison also work? For example "2.0" is bigger than "1.9" even as text strings?

2) Would your check fail, when major version gets over 9? "10." is not valid float, is it

Tested in Python 2.5 shell, but should work in PyS60 too:

>>> [int(x) for x in "1.9.2 final".split(" ")[0].split(".")] > [1,4,5]
True

The idea is to create a list of integers from this version string, e.g. "1.9.2 final" -> [1,9,2].

1. split "1.9.2 final" -> ["1.9.2", "final"]
2. split "1.9.2" -> ["1", "9", "2"]
3. cast integers in string format in the list to integers using list comprehension
4. finally compare two lists of integers which is okay in python :-)

[marcelobarrosalmeida]

Originally Posted by mahesh.sayibabu

This should work on both the PyS60 series

try:
    import btsocket as socket
except:
    import socket

====
Mahesh
PyS60 Team

Perfect. I will take this solution.