[jackofall]

I am storing login and password info as two strings.
but when user try to change its login or password,i need to store that data in next place.( i can't overwrite )
According to the documentation of deleteRecord(int recordid) method,we can't use this id again.
So, that's mean,whenever user try to change this info,it will be written at new place and i need to compare a different record id to validate user info for login.
Can we overwrite the data or can we store data at
record id(1)=login
record id(2)=password
every time .
Thanks for your time!
Regards!

[prakash.raman]

Hi,
have u tried useing "setRecord(int recordId, byte[] newData, int offset, int numBytes)". You don't need to call deleteRecord(), just set the new login , password data at particular record id.

[grahamhughes]

Why can't you overwrite?

I'd recommend you put both pieces of information in the same record, and that you update that record when the details change.

PHP Code:

private static void saveLogin(String username, String password) throws RecordStoreException {
    byte[] data;
    try {
        ByteArrayOutputStream bout = new ByteArrayOutputStream();
        DataOutput dout = new DataOutputStream(bout);

        dout.writeUTF(username);
        dout.writeUTF(password);
        dout.flush();

        data = bout.toByteArray();
    } catch (IOException e) {
        // won't happen, because we're using a ByteArrayOutputStream
    }
        
    RecordStore rs = RecordStore.openRecordStore("login", true);

    try {
        if (rs.getNumRecords() == 0) {
            rs.addRecord(data, 0, data.length);
        } else {
            rs.setRecord(1, data, 0, data.length);
        }
    } finally {
        rs.closeRecordStore();
    }
} 


Graham.

[jitu_goldie]

When login recordstore is empty then use addrecord else when want to overwrite the previous inforation then just use setRecord() function as graham suggests.

[jackofall]

Thank you guys,

"setRecord(int recordId, byte[] newData, int offset, int numBytes)"

This solved my problem.
Cheers